To read numbers in the thousands we put the digits into their place value columns and read from left to right in groups of hundreds, tens and units (ones). We read the hundreds, tens and units within the thousands group and then read the hundreds, tens and units place value columns afterwards.

In this lesson we will look at reading and writing large numbers with up to and including six digits with examples written on a thousands place value chart.

If you are confident in reading and writing three-digit numbers, then you will be able to read any large number.

Here is an example of reading a thousand place value chart:

In the above example, we have a six-digit number.

To make this large number easier to read, we put the digits into groups of three, starting from the right.

We put the digits into groups of three by using a space in between the groups.

The group of three digits on the left is our thousands group. This is how many thousands we have.

Now, that we have put the digits into place value groups of three, we can read the large number.

The group of digits on the right-hand-side is the hundreds, tens and units.

The group of three digits on the left-hand-side is the thousands.

We read from left to right, so we start with the thousands place value group on our chart.

We can think of the digits in this group as hundreds, tens and units.

We have eight hundred and sixty-seven.

Because these three digits are in the thousands group of our place value chart, we have eight hundred and sixty-seven thousand.

Finally, we can read the hundreds, tens and units group.

We have four hundred and eighty-five.

So, the large number is read as:

Eight hundred and sixty-seven thousand, four hundred and eighty-five.

Here is another example of reading a number in the thousands:

We begin by putting the digits into groups of three, starting from the right.

We separate these place value groups with a space.

Now that we have put the digits into groups of three, we can read the large number.

We read our large number from left to right, so we start with the thousands group.

We can start by thinking of this place value group as hundreds, tens and units.

We have 30.

The digits are in the thousands place value group, so we have thirty thousand.

Finally, we read the digits in the hundreds, tens and units place value group of our chart.

We have one hundred and forty-nine.

So, the large number is read as:

Thirty thousand, one hundred and forty-nine.

What is the Long Division Method

Long division is a method used for dividing by larger numbers. Long division is different from short division in that more working out is shown at each stage in order to calculate the remainders.

The long division method is used when dividing by a number that has two or more digits.

The reason we use long division is to provide a structure for dividing by larger numbers. Long division involves writing out the calculations involved in finding a remainder. By showing this level of working out, there is less chance of making a mistake.

How to do Long Division

To do long division, follow these steps:

1. Make a list of the multiples of the number being divided by.
2. Use this list to divide the first digit by this number.
3. Find the greatest number of times that the number divides into the digit and write this above.
4. Subtract the largest multiple of the number from the digit being divided to find the remainder.
5. Write the next digit of the number being divided alongside this remainder.
6. Repeat steps 3 to 5 until there are no more remainders.

Here is an example of dividing a number using long division step-by-step.

In this question we have 8190 ÷ 15.

To set out long division, write the number being divided by to the left of the number being divided. Draw a line to separate the numbers which passes above the number being divided.

The first step is to make a list of the first few multiples of the number being divided by.

The first few multiples of 15 are: 15, 30, 45, 60, 75, 90.

THe next step is to divide the first digit. 15 is larger than 8 and so, we simply write a zero above the 8 because 15 divides into 8 zero times.

We now carry the 8 over as a remainder to make 81. We use the list of multiples to decide how many times 15 divides into 81.

5 × 15 = 75 and 6 × 15 = 90. Therefore, 15 divides into 81 five times. We write a 5 above the line.

The largest multiple of 15 that is less than 81 is 75. The next step is to find the remainder by subtracting 75 from 81.

81 – 75 = 6 and so, the remainder is 6.

The next step is to bring the next digit of the number down alongside this remainder. The next digit of 8190 to consider is the 9. We write the 9 next to the remainder of 6 to make 69.

We now divide 69 by 15.

4 × 15 = 60 and 5 × 15 = 75. Therefore 15 divides into 69 four times. We write a 4 above the line.

The next step is to subtract the largest multiple of 15 that is less than 69. We subtract 60 from 69 to find the remainder.

69 – 60 = 9 and so, the remainder is 9.

The next step is to bring the next digit of 8190 down next to the remainder. The next digit to consider is the 0 and so, we bring this 0 down next to the 9 to make 90.

The next step is to divide 90 by 15.

6 × 15 = 90 and so, 90 divided by 15 equals 6. We write a 6 above the line.

We know that the long division method is complete when there are no more remainders and no more digits of the number being divided.

The answer to a long division question is the combination of digits written above the line.

8190 ÷ 15 = 546

Here is the complete long division process shown as an animation.

Long Division by One Digit

Here are some examples of using the long division method to divide by a single digit number.

It is best to introduce the long division method with an example of dividing by a one-digit number. This is because it makes it easier to concentrate on following the method rather than more complicated multiplication sums.

Here is an example of using the long division method to divide by a one-digit number. We have 376 ÷ 4.

We write the number being divided by to the left of the number being divided. We separate the numbers with a line that also passes above the number being divided.

4 is larger than the first digit of 3. Therefore it does not divide into 3. We write a 0 above the line to show that it divides zero times.

We now look at the first two digits, which are 37.

We divide 37 by 4.

9 × 4 = 36 and 10 × 4 = 40. Therefore 4 divides into 37 nine times. We write a 9 above the line.

The largest multiple of 4 that is less than 37 is 36. We subtract 36 from 37 to find the remainder.

37 – 36 = 1. We write the remainder of 1 below.

We then write the next digit next to this remainder. The next digit in 376 to consider is the 6.

We write the 6 next to the 1 to make 16.

Finally, we divide 16 by 4 to get 4. We write the 4 above the line.

376 ÷ 4 = 94

Here is the complete long division method shown as an animation.

Here is another example of long division by a one-digit number.

We have 380 ÷ 5.

5 divides into 3 zero times with a remainder of 3.

The remainder of 3 combines with the next digit of 8 to make 38.

38 ÷ 5 = 7 remainder 3 because 7 lots of 5 makes 35. We write the 7 above the line.

We subtract 35 from 38 to find the remainder of 3.

We write the next digit of 380 next to this remainder. We write 0 next to the 3 to make 30.

30 ÷ 5 = 6. There is no remainder as this is an exact division. We write the 6 above the line.

380 ÷ 5 = 76

Here is another example of long division by a one-digit number. We have 582 ÷ 6.

6 does not divide into 5. We combine the remainder of 5 next to the next digit along to make 58.

58 ÷ 6 = 9 remainder 4 because 9 lots of 6 is 54. We write a 9 above the line.

We can see the remainder is 4 because 58 – 54 = 4.

We write the next digit of 582 next to this remainder. The digit of 2 combines with the remainder of 4 to make 42.

42 ÷ 6 = 7. We write the 7 above the line.

We can see that 582 ÷ 6 = 97.

Long Division by Two Digits

Here is an example of using long division to divide by a 2-digit number. When dividing by a number that has 2 digits or more, it is useful to list their multiples first.

Here we have 7866 divided by 23.

The first five multiples of 23 are:

1 × 23 = 23

2 × 23 = 46

3 × 23 = 69

4 × 23 = 92

5 × 23 = 115

23 is larger than 7 and so we consider the first 2 digits of 78.

The largest multiple of 23 that is less than 78 is 69.

78 ÷ 23 = 3 remainder 9. We can see the remainder is 9 because 78 – 69 = 9.

We write the next digit of 7866 next to the remainder. The 6 combines with the 9 to make 96.

The largest multiple of 23 that is less than 96 is 92.

96 ÷ 23 = 4 remainder 4. We can see that the remainder is 4 because 96 – 92 = 4.

We write the next digit of 7866 next to the remainder. The 6 combines with the 4 to make 46.

46 ÷ 23 = 2. This is an exact division and so, we have finished this long division method.

7866 ÷ 23 = 342

How to Find the Area of a Parallelogram

To find the area of a parallelogram, multiply the base by the height. The base is the length of one side and the height is the direct distance between the base side and the side opposite to it. The base and the height must be at right angles to each other.

The area of a parallelogram is calculated by multiplying the base and its perpendicular height. Perpendicular height tells us that the base and the height need to be at right angles to each other.

Here is an example of calculating the area of a parallelogram.

The area of a parallelogram is base x height. The base and height are chosen as being two lengths that are at right angles to each other.

The base of a parallelogram is the outer side length, which runs along the bottom. Here the base is 11 cm.

The height of a parallelogram is the length between the base and the side opposite to the base. The height of this example is 6 cm.

The area is 11 cm x 6 cm = 66 cm².

Area is always written as units squared. Because the base and height lengths were measured in centimetres, the area is measured in centimetres squared, cm².

Here is another example of finding the area of a parallelogram where the base is not on the bottom of the parallelogram.

We do not know the bottom-most side length of this shape.

The base is chosen as the known outer side length. The base in this example is 10 cm. We choose this even though it is not on the bottom of the parallelogram.

The height is then the length between this base side and the side opposite to the base. The height is 8 cm.

The area of a parallelogram is base x height.

The area is 10 cm x 8 cm = 80 cm².

If a parallelogram is on its side, we can imagine it rotated around to see what its base would be.

Now we can see the base and height more easily.

What is the Formula for the Area of a Parallelogram?

The formula for the area of a parallelogram is A = b x h, where b is the base length and h is the perpendicular height. This formula can be written more simply as A = bh.

Here is an example of using the area of a parallelogram formula.

The base is 5 m and the height is 8 m.

A = b x h.

b = 5 and h = 8, so A = 5 x 8 = 40.

Therefore the area of this parallelogram is 40 m². Since we measured the sides in metres, the area is measured in metres squared.

Here is another example of using the formula to find the area of a parallelogram.

The base is 3 mm. The perpendicular height to this base is 7 mm. It is 7 mm from the base to the top of the parallelogram.

A = bh. This means that we multiply b and h together.

A = 3 mm x 7 mm = 21 mm².

This means that the area of this parallelogram is 21 mm².

Why is the Area of a Parallelogram Base Times Height?

The area of a parallelogram is base times height because it can be rearranged into a rectangle with the same area. A rectangle is a special type of parallelogram. The area of a rectangle is base times height and so, the area of a parallelogram is also base times height.

The area of a rectangle is found by multiplying the base by its height.

Each parallelogram can be rearranged to form a rectangle. We start by moving this marked triangle over to the right hand side.

We now have a rectangle.

The area of a rectangle is written as length x width or base x height.

Therefore the area of a parallelogram is also base x height.

It is important to note that the base and height of a rectangle meet at right angles and so, the base and height of a parallelogram also need to meet at right angles in order to use the area of a parallelogram formula.

A Rectangle a Type of Parallelogram

A rectangle is a type of parallelogram that has four right angles. A parallelogram is a shape with four sides and two pairs of parallel sides. A rectangle meets this definition and so, it is also a type of parallelogram.

A parallelogram is a type of quadrilateral, which means that it has four sides.

A parallelogram is called a parallelogram because it has two pairs of parallel sides.

A rectangle is a special type of parallelogram because it has four sides and two pairs of parallel sides.